2^2x+1=1/16

Solution for 2^2x+1=1/16 equation:

2^2x+1=1/16

We move all terms to the left:

2^2x+1-(1/16)=0

We add all the numbers together, and all the variables

2^2x+1-(+1/16)=0

We get rid of parentheses

2^2x+1-1/16=0

We multiply all the terms by the denominator


2^2x*16-1+1*16=0

We add all the numbers together, and all the variables

2^2x*16+15=0

Wy multiply elements

32x^2+15=0

a = 32; b = 0; c = +15;
Δ = b2-4ac
Δ = 02-4·32·15
Δ = -1920
Delta is less than zero, so there is no solution for the equation